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(Solved): There are 51 computers on a network with IP addresses 192.168.10.1 - 192.168.10.100. Prove that at l ...
There are 51 computers on a network with IP addresses 192.168.10.1 - 192.168.10.100. Prove that at least 2 computers have consecutive IP addresses.
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Notation : sif(x) = smallest integer greater han or equal to x. This is same as saying if we choose 51 numbers from 1 to 100 then we would have atleast 2 consecutive
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