(Solved): The common tangent BC of a reversed curve is 600m too long and has a bearing of S45E. AB is tangen ...

The common tangent BC of a reversed curve is 600m too long and has a bearing of S45°E. AB is tangent of the first curve whose bearing is N70°E while CD is a tangent of the second curve whose bearing is N30°E. A is the point of curvature while D is the point of tangency. If the degree of the curvature at D is 4°,

find the stationing of PC if PRC is at sta 16+420.