6. Three different distributions
There are 559 full-service restaurants in Delaware. The mean
number of seats per restaurant is 99.2. [Source: Data based on the
2002 Economic Census from the US Census Bureau.]
Suppose that the true population mean µ = 99.2 and standard
deviation ? = 20.8 are unknown to the Delaware tourism board. They
select a simple random sample of 50 full-service restaurants
located within the state to estimate µ. The mean number of seats
per restaurant in the sample is M = 103.4, with a sample standard
deviation of s = 18.2.
The standard deviation of the distribution of sample means (that
is, the standard error, ?MM) is . (Note: Although
µ and ? are unknown to the Delaware tourism board, they are known
to you for the purposes of calculating these answers.)
The standard or typical average difference between the mean
number of seats in the 559 full-service restaurants in Delaware (µ
= 99.2) and one randomly selected full-service restaurant in
Delaware is .
The standard or typical average difference between the mean
number of seats in the sample of 50 restaurants (M = 103.4)
and one randomly selected restaurant in that
sample is .
The standard or typical average difference between the mean
number of seats in the 559 full-service restaurants in Delaware
(µ = 99.2) and the sample mean of any sample of
size 50 is .
The z-score that locates the mean number of seats in the
Delaware tourism board’s sample (M = 103.4) in the distribution of
sample means is .
Use the unit normal tables and accompanying figures to answer
the question that follows. To use the tables, select the desired
range of z-score values. A table of the proportions of the normal
distribution corresponding to that range of z-scores will
appear.
Suggestion: Make a sketch of the area under the normal
distribution you are seeking. This sketch will help you determine
which column(s) of the normal table to use in determining the
appropriate probability.