1 12) e) Using the fourth order Runge-Kutta Method, with a step-size of h approximate y(12) if y(0) = 40, yields: koi = ko2 = ko3 = k04 = and thus y(1/12) = 0 (1/12) – yi =

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1 12) e) Using the fourth order Runge-Kutta Method, with a step-size of h approximate y(12) if y(0) = 40, yields: koi = ko2 = ko3 = k04 = and thus y(1/12) = 0 (1/12)  yi =

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